3x^2-40=2(x^2+30)

Solution for 3x^2-40=2(x^2+30) equation:

Simplifying
3x2 + -40 = 2(x2 + 30)

Reorder the terms:
-40 + 3x2 = 2(x2 + 30)

Reorder the terms:
-40 + 3x2 = 2(30 + x2)
-40 + 3x2 = (30 * 2 + x2 * 2)
-40 + 3x2 = (60 + 2x2)

Solving
-40 + 3x2 = 60 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-40 + 3x2 + -2x2 = 60 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-40 + 1x2 = 60 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-40 + 1x2 = 60 + 0
-40 + 1x2 = 60

Add '40' to each side of the equation.
-40 + 40 + 1x2 = 60 + 40

Combine like terms: -40 + 40 = 0
0 + 1x2 = 60 + 40
1x2 = 60 + 40

Combine like terms: 60 + 40 = 100
1x2 = 100

Divide each side by '1'.
x2 = 100

Simplifying
x2 = 100

Take the square root of each side:
x = {-10, 10}